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Казвам такси каталог ioners opløselighed гланц Остаряла Том Одрит

$\begin{array}{llllll} \textup{opl\o selighedsprodukt:}\\&& \left [ Ba^{2+} \right ] \cdot \left [ S{O_4}^{2-} \right ]=1.5\cdot 10^{-9}\;\mathrm{M^2}\\\\ \textup{n\aa r der i forvejen er}\\ 0.005\;\mathrm{M}\; Ba^{2+}\textup{:}\\&&(0.005+x)\cdot x=1.5\cdot 10^{-9}\\\\&&x^2+0.005x-1.5\cdot 10^{-9}=0,\quad x>0\\\\&& x=3.0\cdot 10^{-7}\;\mathrm{\frac{mol}{L}}=7.0\cdot 10^{-5}\;\mathrm{\frac{g}{L}}=0.07\;\mathrm{\frac{mg}{L}} \\\\ \textup{I en 0.005 M opl\o sning}\\\textup{af }Ba^{2+}\textup{-ioner}\\ \textup{kan der opl\o ses}&&0.07\;\mathrm{mg }\; BaSO_4\textup{ pr liter opl\o sning.} \end{array}$

$\begin{array}{lllll} \textup{Den mol\ae re}\\ \textup{opl\o selighed:}&s=\frac{0.0140\cdot 10^{-2}\;g}{\left (1\;L \right )\cdot \left ( 811.57\;\frac{g}{mol} \right )}=1.72505\cdot 10^{-7}\;M\\\\ \textup{Ionisering:}&Pb_3(PO_4)_2\,_{\textit{(s)}}\;\rightleftharpoons \;3\,Pb^{2+}\,_{\textit{(aq)}}\;+\;2\,P{O_4}^{3-}\\\\ \textup{Opl\o seligheds-}\\ \textup{produktet:}&\left [ Pb^{2+} \right ]^3\cdot \left [ P{O_4}^{3-} \right ]^2=K_{sp}\\\\& \left ( 3s \right )^3\cdot \left ( 2s \right )^2=K_{sp}\\\\& 27s^3\cdot 4s^2=K_{sp}\\\\& 108\cdot s^5=K_{sp}\\\\& K_{sp}=108\cdot \left (1.72505\cdot 10^{-7}\;M \right )^5=1.64981\cdot 10^{-32}\;M^5 \end{array}$

$\begin{array}{lllll} &\left [ Al^{3+} \right ]\cdot \left [ F^- \right ]^3=K_{sp}\\\\\textup{kaldes den mol\ae re}\\\textup{opl\o selighed for }s\\\textup{haves:}&s\cdot (3s)^3=1.10\cdot 10^{-3}\; M^4\\\\&27s^4=1.10\cdot 10^{-3}\; M^4\\\\&s=\left ( \frac{1.10\cdot 10^{-3}\; M^4}{27} \right ) ^{\frac{1}{4}}=0.079893\; M\\\textup{omregnet}\\\textup{opl\o selighed}&\left (0.079893\; \frac{mol}{L} \right )\cdot \left ( 83.977\; \frac{g}{mol} \right )=6.71\; \frac{g}{L}=0.671\; \frac{g}{100\; mL} \end{array}$